If the perimeter of a rectangle is 102 feet and the length is three less than eight times the width, find the width

Question

I need a clear step by step explanation please. Thank you

Answer 1

P=102 L=8W-3

P/2 = 51 = L+W = 8W-3 +W = 9W-3

9W-3 = 51

9W = 51+3 = 54

W = 54/9 = 6 feet wide

L=48-3 = 45

2(45+6) = 2(51) = 102