Given p(x)=x-7/?, what would the denominator need to be in order for the function to have vertical asymptotes at x=1 and x=-6?

Answer 1

y = (x-7)/(x-1)(x+6) has vertical asymptotes at x=1 and x=-6

as x approaches either 1 or -6, y approaches infinity or negative infinity

y=(x-7)/(x^2 +5x -6)