Urgent statistic

Question

 Do you mind answering this as well? Suppose that you have 9 cards. 4 are green and 5 are yellow. The 4 green cards are numbered 1, 2, 3, and 4. The 5 yellow cards are numbered 1, 2, 3, 4, and 5. The cards are well shuffled. You randomly draw one card. • G = card drawn is green • Y = card drawn is yellow • E = card drawn is even-numbered Enter the probability as a fraction.

P(G | E) = Enter the probability as a fraction.

P(G AND E) = Enter the probability as a fraction.

 P(G OR E) =

Answer 1

P(G|E). There are four even cards, 2 each from green and yellow, so there is a 2/4 = 1/2 chance that if an even card is drawn it is green.

P(G and E) There are two cards that are both green and even out of 9 cards so there is a 2/9 chance that you draw a green and even card.

P(G or E). There are 4 cards that are green, 4 cards that are even and 2 cards that are both green and even. Thus there 4 + 4 - 2 = 6 cards out of 9 that are uniquely green or even (but not both), so there is a 6/9 = 2/3 chance that you draw a green or even card.