Point P(3,5) is on the terminal arm of angle θ in standard position. calculate sin θ
For point (3,5)
Adjacent = 3
Opposite = 5
So hypotenuse = √ ( 32 + 52 ) = √ 9 +25 = √34 = 5.83
Sinθ = Opposite / Hypotenuse = 5/5.83 = 0.858
so θ = Sin -1 ( 0.858 ) = 59.0 degree