We can think about this in terms of transformations -- shifts, stretches, shrinks, etc.
In this case, f(4x+2) represents 2 horizontal transforms applied to the graph, meaning the range stays as it is, f(x) ε (6 , 8].
We should rewrite the function with the 4 factored out to put it in standard form: f(4(x+1/2))
This expression indicates the graph will first be shrunk by a factor of 4, ie the points will move 4 times closer to the y-axis than they were, or the x-coordinates will be divided by 4. Then, the points are shifted left by 1/2, meaning we subtract 1/2 from the x-coordinates.
Applying these two transforms gives x ε (- 3 , 1] , which is the domain of the new function.
You can verify that applying 4x + 2 to these new endpoints gives the old endpoints of the domain interval.

Josh F.
03/11/21
Samuel B.
What if the function was 6 f(x) + 4? How would you go about solving this?03/13/23

Josh F.
03/13/23
Peter L.
Thanks a lot, this is really helpful03/11/21