Lily E.

asked • 03/07/21

feet per second help

A rotating light is located 11 feet from a wall. The light completes one rotation every 4 seconds. Find the rate at which the light projected onto the wall is moving along the wall when the light's angle is 20 degrees from perpendicular to the wall.

1 Expert Answer

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Anthony T. answered • 03/07/21

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Lily E.

Hello, the 383 ft/sec is incorrect. Can you please fix it?
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03/07/21

Anthony T.

I think I found the error. The quantity to evaluate is the distance change along the wall. The distance of the light along the wall is D = 11tanθ. The derivative of D with respect to time is dD/dt = 11/cos^2 θ x 90 deg/sec = 1121 ft/sec. I hope this is right. Please let me know. If not, perhaps you should post it again to get another tutor's input.
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03/07/21

Anthony T.

I found a similar problem on-line. When I did it, my results were too high. Upon analyzing what I did vs. what they did, I found that they expressed dθ/dt in radians\sec rather than degrees/sec. So, dθ/dt in radians per second is pi/2. Substituting this for 90 in the problem above gives 19.5 ft/sec as the result. The other problem I tried for you probably has the same error. Please let me know about the latest result.
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03/08/21

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