
Anthony T. answered 03/07/21
Patient Science Tutor
Draw a diagram of a light 11 feet from a wall (perpendicular to wall). Then draw a line from the light to the wall at some angle θ to the perpendicular line. Using trig the distance from the light to the wall at an angle θ is given by
D = 11/cosθ. The rate of change of the angle as the light rotates is dθ/dt which is 360º/4sec = 90º /sec.
Differentiating, dD/dt = 11 d(1/cosθ)/dt = 11 x - 1/cos2θ x -sin θ x dθ/dt = 11 x 1/cos220º x sin20º x 90º/sec
Evaluating the trig functions and calculating, dD/dt = 383 ft/sec
Check my math.

Anthony T.
I think I found the error. The quantity to evaluate is the distance change along the wall. The distance of the light along the wall is D = 11tanθ. The derivative of D with respect to time is dD/dt = 11/cos^2 θ x 90 deg/sec = 1121 ft/sec. I hope this is right. Please let me know. If not, perhaps you should post it again to get another tutor's input.03/07/21

Anthony T.
I found a similar problem on-line. When I did it, my results were too high. Upon analyzing what I did vs. what they did, I found that they expressed dθ/dt in radians\sec rather than degrees/sec. So, dθ/dt in radians per second is pi/2. Substituting this for 90 in the problem above gives 19.5 ft/sec as the result. The other problem I tried for you probably has the same error. Please let me know about the latest result.03/08/21
Lily E.
Hello, the 383 ft/sec is incorrect. Can you please fix it?03/07/21