Raymond B. answered 03/02/21
Math, microeconomics or criminal justice
R = 60x - 0.5x^2
take the derivative and set equal to zero, then solve for x to get the revenue maximizing output level
R' = 60 -x = 0
x = 60, plug that value into the R(x) equation
R=60(60) - 0.5(60)^2 = 3600-1800 = $1800 = max revenue when output = 60 units