need tangent line immediately please
Let: f(x) = 5x^3 + 13x - 3
The derivative function is: f ' (x) = ((5(x+h)^2 + 13(x+h) - 3) - (5x^2 + 13x - 3)) / h
The f ' (x) = df/dx = 10x + 13
Based on this information, I need to find the tangent line for f(x) where x = 2. Can someone please help me find this? I need immediate help please.
I think the equation would be y = 33(2) + b, but I'm not sure if this equation is right, and if this equation is right, I don't know what b would be.
Please help me find the tangent line!