Given: 2z3-3z2+8z+6 ÷ 2z+1
This expression can be rewritten as follows:
(2z3-3z2+8z+6) ÷ (2z + 1) =
[z (2z2 -3z + 8 + 6)] ÷ (2z + 1) =
[z (2z2 - 3z + 14)] ÷ (2z + 1) =
[z(2z - 7)(z - 2)] ÷ (2z + 1).
This expression is the final expression.