A plane flies 650 km with a bearing of N 34̊ E from A to B. The plane then flies 1070 km to C from B toward the southeast (Not 45̊). Find the bearing of the flight from B to C, as shown

Question

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Answer 1

Refer to the figure which cannot be copied because it exceeds the character count of this inflexible rectangle

Draw a line from B to the right parallel to AC

Law of Sines gives: (Sin56)/1070 = (Sin[ACB]/650

Sin[ACB] = 0.33969

ACB = 19.86°

Drawing a line from B perpendicular to AC at D, Angle DBC = 70.14°

Since the line from B to the right parallel to AC is bearing 90°,and adding

19.36° to it yields a bearing of 109.36° from B to C