Find the two square roots of...

Question

3+3√ 3i (Give your answers in the form a + bi, where a and b are real numbers. Enter your answers as a comma-separated list.)

Answer 1

rewrite, z=[6*(cos(π/3+2πk)+i*sin(π/3+2πk)]⁽¹²⁾ k=0.1

z₁=+/-√6*(cos(π/6)+i*sin(π/6))

z₂=+/-√6(cos(7π/6+i*sin(7π/6))

even without the +/- in front of √6, z₁ is the negative of z_2, so the +/- is irrelevant