Yefim S. answered 02/25/21
Math Tutor with Experience
z1 = 5√2(cos3π/4 + isin3π/4); z2 = 5√2(cosπ/4 + isinπ/4).
z1z2 = 50(cosπ + isinπ) = - 50
z1/z2 = cosπ/2 + isinπ/2 = i
Zoe S.
asked 02/25/21Use trigonometric forms to find z1z2 and z1/z2. (Enter your answers in the form a + bi.)
z1 = −5 + 5i, z2 = 5 + 5i
z1z2= ?
z1/z2= ?
Yefim S. answered 02/25/21
Math Tutor with Experience
z1 = 5√2(cos3π/4 + isin3π/4); z2 = 5√2(cosπ/4 + isinπ/4).
z1z2 = 50(cosπ + isinπ) = - 50
z1/z2 = cosπ/2 + isinπ/2 = i
First of all move the minus sign in the numerator out from and then divide out the 5 so that you have
-(1-i)/(1+i)
Now multiply the numerator and denominator (both) by 1-i to get
1(1-i)2/2
You can now expand the numerator to get a form like a+bi...just remember to being along the 2 in the denominator!
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