J.R. S. answered 02/25/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
One more time...
ln (k2/k1) = -Ea/R (1T2 - 1/T1) ARRHENIUS EQUATION
k1 = 5.91x10-4 s-1
k2 = ?
Ea = 123 kJ/mol
R = 0.008314 kJ/Kmol
T1 = 462K
T2 = 502K
ln (k2/5.91x10-4) = - 123/0.008314 (1/502 - 1/462)
ln (k2/5.91x10-4) = -14,794 (0.00199 - 0.00216)
ln (k2/5.91x10-4) = 2.51
(k2/5.91x10-4) = 12.3
k2 = 7.27x10-3 s-1
