J.R. S. answered 02/24/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
....step 1.....fast:......NO2 + CO <==> ONOCO
.....step 2.....slow:....ONOCO ==> NO + CO2
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(1). NO2 + CO ==> NO + CO2 ... overall reaction (sum the 2 elementary steps)
(2) NONOCO is an intermediate
(3) From step 1 (fast),... k1[NO2][CO] = k2[ONOCO]
solving for [NONCO] we have
[ONOCO] = k1/k2 [NO2][CO] ... we can now substitute this into the rate law for step 2 (slow step):
From step 2 (slow) ... rate = k3[ONOCO]
rate = k3 * k1/k2 [NO2][CO]
rate = k' [NO2][CO] ... complete rate law for overall reaction