James C. answered 02/24/21
BS in Mathematics with 20+ years of teaching experience
2L + 2W = 72
W = 10
2L + 2(10) = 72
2L + 20 = 72
2L = 52
L = 26
2L + 2W = 72
2L = 72 - 2W
L = (72-2W)/2
L = 36 - W
Elissa M.
asked 02/24/21The perimeter of a rectangle is 72 cm. The relationship between the length, the width, and the perimeter of the rectangle can be described with the equation 2•length+2 width=72
find the length, in centimeters, if the width is
a. 10 cm
b. W cm
James C. answered 02/24/21
BS in Mathematics with 20+ years of teaching experience
2L + 2W = 72
W = 10
2L + 2(10) = 72
2L + 20 = 72
2L = 52
L = 26
2L + 2W = 72
2L = 72 - 2W
L = (72-2W)/2
L = 36 - W
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