A bag contains 12 balls

Question

A bag contains 12 balls, 8 red and 4 blue. You reach in the bag and pick 3 balls at random (without replacement). What is the probability that at least 2 of the balls will be blue? Round off answers to 4 decimal places. 

Answer 1

P(ATLEAST 2 BALLS ARE BLUE)= P(2 BLUE AND ONE RED) +P(ALL THREE ARE BLUE)

= ((4*3*8)/(12*11*10)) + ((4*3*2)/(12*11*10))

=0.09090