
Mark M. answered 02/21/21
Tutor
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(278)
Mathematics Teacher - NCLB Highly Qualified
sin (x / 2) = ±[√(1 - cos x) / 2]
sin2 (x / 2) = (1 - cos x) / 4
4 sin2 (x - 2) = 1 - cos u
Aerin H.
asked 02/21/214 sin2(x/2)
= ___________
Mark M. answered 02/21/21
Mathematics Teacher - NCLB Highly Qualified
sin (x / 2) = ±[√(1 - cos x) / 2]
sin2 (x / 2) = (1 - cos x) / 4
4 sin2 (x - 2) = 1 - cos u
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