
Yuri O. answered 02/19/21
16 years online, 464 former SAT problems drilled down
ΔAGC is the right triangle (face DHGC is ⊥ to the base ABCD, therefore, GC⊥AC).
AG = √188 (hypotenuse)
GC = 10 (one leg)
Calculating AC (2nd leg) from ΔAGC:
AC2 = 188 - 100 = 88 → Pythagorean theorem
ΔADC is the right triangle (base is a square)
AD = DC = a → legs
AC → hypotenuse
AC2 = 2a2
a2 = AC2/2 → the area of the base of cuboid
h = GC = 10 → height of cuboid
Calculating the volume of cuboid:
V = a2 • h = (88/2) • 10 = 440 (cm2)
P.S.
I made a picture but it was too large to meet the limitations of the posts.
ABCD is the square base of cuboid.
EFGH is the top square, which is parallel to the base.