Math problem in des

Question

How much 36% acid solution should be added to 12%  acid solution to make 192mL of a 14% acid solution?

How many ml of 36%

How many ml of 14%

Answer 1

36X + 12(192-X) = 14(192)

36X -12X = 14(192)-12(192) = 2(192)

24X = 2(192)

12X = 192

X = 192/12 = 16 mL of 36% acid

192-X = 192-16 = 176 mL of 12% acid

to get 192 mL of 14% acid

12 is much closer to 14 than 36 is near 14, so you want much more of 12%

12 is within 2 of 14, 36 is within 22 of 14

22 is 11 times 2

you want 11 times more 12% than 36% acid

176 = 11 times 16