
Patricia D. answered 02/17/21
Honors and AP tutor for five years
Adult tickets: $3.50
Student tickets: $2.50
One performance = 321 tickets = $937.50
Let's have a = number of adult tickets and s = number of student tickets. With the given information, we know that some number of adult tickets COMBINED with some other number of student tickets total 321 tickets. Therefore, our system of equations are:
a + s = 321 (i)
3.50a + 2.50s = 937.50 (ii)
In equation (i), a = 321 - s. If we substitute that into equation (ii), we get:
3.50(321-s) + 2.50s = 937.50
1123.50 - 3.50s + 2.50s = 937.50 Distribute the 3.50 according to PEMDAS.
1123.50 - 1s = 937.50 Add s to the both sides of the equation, and subtract 937.50 to both 187.00 = s sides, getting rid of the negative s value.
a + 187 = 321
a = 134
134 adult tickets & 187 student tickets were sold
Faiz S.
Thank you so much! You will truly repair my GPA.02/18/21