sin 1125 = sin 45 = (sqroot2)/2
sin 480 = sin120 = (sqroot 3)/2
so this is (sqroot 2+ sqroot 3)/2
Aerin H.
asked 02/15/21(a) sin(1125° + 480°)
= _________
(b) sin(1125°) + sin(480°)
= __________
sin 1125 = sin 45 = (sqroot2)/2
sin 480 = sin120 = (sqroot 3)/2
so this is (sqroot 2+ sqroot 3)/2
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