James C. answered 02/14/21
BS in Mathematics with 20+ years of teaching experience
y = kx
Substitute 5 for x and 1 for y. Then solve for x.
1=k(5)
k = 1/5
y = (1/5)x
Ethan B.
asked 02/14/21James C. answered 02/14/21
BS in Mathematics with 20+ years of teaching experience
y = kx
Substitute 5 for x and 1 for y. Then solve for x.
1=k(5)
k = 1/5
y = (1/5)x
Mark M. answered 02/14/21
Mathematics Teacher - NCLB Highly Qualified
Direct variation is in the form
y = kx
For the numbers given
y = (1/5)x
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