
Bradford T. answered 02/12/21
MS in Electrical Engineering with 40+ years as an Engineer
v(t) = ∫a(t)dt
s(t) = ∫v(t)dt
v(t) = ∫<cos(t), 5sin(t)> dt = <sin(t), -5cos(t) + 2>
s(t) = ∫<sin(t), -5cos(t)+2>dt = <-cos(t) + 2, -5sin(t) + 2t>
Samir R.
asked 02/12/21Given an acceleration vector, initial velocity (u0, v0), and initial position (x0, y0), find the velocity and position vector for t >= 0.
a(t)=<cos(t), 5sin(t)>
<u0, v0> = <0, 2>
<x0, y0> = <2, 0>
Bradford T. answered 02/12/21
MS in Electrical Engineering with 40+ years as an Engineer
v(t) = ∫a(t)dt
s(t) = ∫v(t)dt
v(t) = ∫<cos(t), 5sin(t)> dt = <sin(t), -5cos(t) + 2>
s(t) = ∫<sin(t), -5cos(t)+2>dt = <-cos(t) + 2, -5sin(t) + 2t>
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