the hypotenuse = sqrt(3^2 + 5^2) = sqrt(34)
sin (theta) = other side/hypotenuse = 3/sqrt(34)
cos(theta) = base/hypotenuse = 5/sqrt(34)
csc(theta) = 1/sin(theta) = sqrt(34)/3
cot(theta) = cos(theta)/sin(theta) = 3/5
Babe R.
asked 02/10/21cotθ =
cscθ =
Sinθ =
the hypotenuse side is empty
the other side is 3
the base is 5
the θ is at the bottom between the hypotenuse and base
Give exact values, not decimal approximations.
the hypotenuse = sqrt(3^2 + 5^2) = sqrt(34)
sin (theta) = other side/hypotenuse = 3/sqrt(34)
cos(theta) = base/hypotenuse = 5/sqrt(34)
csc(theta) = 1/sin(theta) = sqrt(34)/3
cot(theta) = cos(theta)/sin(theta) = 3/5
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