mean median mode and midrange

Question

Below are the jersey numbers of 11 players randomly selected from a football team. Find the​ range, variance, and standard deviation for the given sample data. What do the results tell​ us?

63   96   60   26   58   7   18   4   49   51   80

  

Range=



​(Round to one decimal place as​ needed.)

Answer 1

A bit more detail for those interested.

Range = max - min = 96 - 4 or 92

Variance = the mean squared error or 878.4727

Standard Deviation = √ Variance = √ 878.5296 or 29.64

if the mean, median, mode, and mid range are also required (from title)

the data must be ordered and a counted.

Mean = sum of all values divided by 11 or 46.55

Median = middle value (the 6th value) 0r 51

Mode - taken from histogram - distribution has 2 modes. 50, and 10 (smaller)

MidRange - (max+min) / 2 - (96+4)/2 or 50

Observation: From this data , since the MidRange, Mode, and Median are close it would imply a symmetric distribution, but the large standard deviation, limits on the values to positive values only indicate otherwise. A histogram clearly shows that the distribution is not normal or uniform.

note: these can be hand calculated

(here is a good example)https://campus.datacamp.com/courses/intro-to-statistics-with-r-introduction/chapter-five-measures-of-variability?ex=6

The results given were calculated using a TI-86 calculator.

Answer 2

are the mean/average, median, mid-range, variance, and standard deviation respectively