Hi Jackie R.
You can also just factor it
9x2 -12x + 4
9x2 -12x + 4 = 0
(3x - 2)(3x - 2)
3x - 2 = 0
3x = 2
x = 2/3
This choice B) 1 real
You can also check it
9(2/3)2 -12(2/3) + 4= 0
9(4/9) - 8 + 4 =0
4 - 8 + 4 = 0
8 -8 = 0
I hope this helps.
Jackie R.
asked 02/01/21Identify the number and type of solutions for the equation 9x2 − 12x + 4 = 0.
A.) 1 nonreal complex
B.) 1 real
C.) 2 nonreal complex
D.) 2 real
Please give and only give the explanation and the solution.
Hi Jackie R.
You can also just factor it
9x2 -12x + 4
9x2 -12x + 4 = 0
(3x - 2)(3x - 2)
3x - 2 = 0
3x = 2
x = 2/3
This choice B) 1 real
You can also check it
9(2/3)2 -12(2/3) + 4= 0
9(4/9) - 8 + 4 =0
4 - 8 + 4 = 0
8 -8 = 0
I hope this helps.
The most straightforward way to do this is to use the quadratic formula, which gives the solutions as
x1, x2 = (-b + sqrt(b^2 - 4*a*c))/(2*a).
Here, a = 9 (the coefficient of x^2), b = -12 (the coefficient of x), and c = 4 (the constant). Thus, we get
x1, x2 = (12 + sqrt(12^2 - 4*9*4))/(2*9) = (12 + sqrt(144 - 144))/(2*9) = (12 + sqrt(0))/(2*9) = 12/18 = 2/3.
Thus, there's one real solution, and the answer is (B).
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