The tail probability = (1-0.6083)/2 = 0.19585
We need the standard normal value, z, where P(z<=a) = 0.19585
-a = InvNorm(0.19585,0,1) = -0.8565
a = 0.8565
Iy G.
asked • 01/31/21In a standard normal distribution, If P(-a < z < a) = 0.6083, Find a.
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