Problem Solving

Question

Over the past 30 games between team A and team B, team A has won 14 times, team B has won 11 times and the game has ended in a draw 5 times. If these two teams played 9 games this season, What is the probability that team A would win 5 games, team B would win 3 games, and the remaining game would be a draw?

Answer 1

Prob(A) = 14/30 = 7/15

Prob(B) = 11/30

Prob(tie) = 5/30 = 1/6

Note that 7/15 + 11/30 + 1/6 = 14/30 + 11/30 + 5/30 = 30/30 = 1 = 100%

9 games

----------

7/15 * 9 = 7/15 * 9/1 = 63/15 = 21/5 = 4 and 1/5 won by A

11/30 * 9 = 11/30 * 9/1 = 99/30 = 33/10 = 3 and 3/10 won by B

1/6 * 9 = 1/6 * 9/1 = 9/6 = 3/2 = 1 and 1/2 tie

Again, not that 21/5 + 11/10 + 3/2 = 42/10 + 33/10 + 15/10 = 90/10 = 9

You can say: A wins 4, B wins 3, and 2 ties