Tom K. answered 01/31/21
Knowledgeable and Friendly Math and Statistics Tutor
Note that there are 4 labelled points plus (0, 0) on the left side and 5 labelled points on the right side. That actually makes everything easy. The slope at (-3, -1) of g(x) being undefined being mapped from (0, 0) confirms the reasonableness of this procedure.
g(x) =c f(x--3) - 1 = c f(x+3) - 1
We only need to find c.
Note that we have (-2, -3)
Then, as we had (1, 1) before,
g(-2) = c f(-2+3) - 1 = c f(1) - 1 = c * 1 - 1 = c - 1
-3 = c - 1
-2 = c
g(x) = -2 f(x+3) - 1 = -2 (x+3)1/3 - 1
To check
g(-11) = -2 (x+3)1/3 - 1 = -2 (-11+3)1/3 - 1 = -2 (-8)1/3 - 1 = -2 * -2 - 1 = 3
g(-4) = -2 (x+3)1/3 - 1 = -2 (-4+3)1/3 - 1 = -2 (-1)1/3 - 1 = -2 * -1 - 1 = 1
g(-3) = -2 (x+3)1/3 - 1 = -2 (-3+3)1/3 - 1 = -2 (0)1/3 - 1 = -2 * 0 - 1 = -1
g(-2) = -2 (x+3)1/3 - 1 = -2 (-2+3)1/3 - 1 = -2 (1)1/3 - 1 = -2 * 1 - 1 = -3
g(5) = -2 (x+3)1/3 - 1 = -2 (5+3)1/3 - 1 = -2 (8)1/3 - 1 = -2 * 2 - 1 = -5