So when the mass is 1/2 the original value you have the equation
500= 1000e^-.05t
e^-.05t = 500/1000
e^-.05t=.5. Now take the natural log of both sides of the equation
-.05t=ln.5
t= ln.5/-.05= 13.863yrs rounded to the nearest thousand
Jujuba D.
asked 01/29/21I really need help solving this problem for my probability and statistics class. I need to show the algebra I used to achieve my results.
The mass of a radioactive substance remaining after t years is given by:
M=1000Xe^-0.05t
Find the exact time when the mass will reach half its original value.
So when the mass is 1/2 the original value you have the equation
500= 1000e^-.05t
e^-.05t = 500/1000
e^-.05t=.5. Now take the natural log of both sides of the equation
-.05t=ln.5
t= ln.5/-.05= 13.863yrs rounded to the nearest thousand
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