James C. answered 01/26/21
BS in Mathematics with 20+ years of teaching experience
Let a = cost of an apple and p = cost of a pear.
We can make two equations from the information we are given:
2a + 6p = 5
3a + 1p = 3.5
Now we have a system of equations we can solve. I would solve the 2nd equation for p and use the substitution method to get our answers
p = 3.5 - 3a
Now we substitute 3.5 - 3a in for p in the 1st equation
2a + 6(3.5 - 3a) = 5
Now we solve for a.
2a + 21 - 18a = 5
-16a = -16
a = 1
Now we substitute 1 for a in p = 3.5 - 3a to find p.
p = 3.5 -3(1)
p = .5
So apples cost $1 and pears cost 50 cents