There is a line that includes the point (2, –10) and has a slope of –8 What is its equation in slope-intercept form?

Answer 1

You can use either y=mx + b to find the y-intercept of your line, then substitute the slope and y-intercept values back in: -10 = -8(2) + b multiply -8(2) -10 = -16 + b add 16 to both sides b = 6

Substitute m = -8 and b = 6 into y = mx + b y = -8x + 6

Or use point slope y - y₁ = m(x - x₁ ) where you substitute values in for x and y but leave the y and x as variables, also substitute the value of m y - (-10) = -8(x - 2) distribute the -8 and fix the double - -

y + 10 = -8x + 16 subtract 10 from both sides to get y by itself y = -8x + 6

Answer 2

Use the point slope formula: y-y₁=m(x-x₁)

m= slope

x₁= x value

y₁= y value

once you’ve plugged in the coordinates & slope you solve for y a.k.a the slope intercept formula y=Mx+b