
Bradford T. answered 12/17/20
MS in Electrical Engineering with 40+ years as an Engineer
(x+3) is a common term, so we can factor it out from above, leaving 2x+5
(x+3)(2x-5)
Jahiem C.
asked 12/17/20Sow work please I need this so I can get this work done teacher giving mad work.
Bradford T. answered 12/17/20
MS in Electrical Engineering with 40+ years as an Engineer
(x+3) is a common term, so we can factor it out from above, leaving 2x+5
(x+3)(2x-5)
Just factor out the common factor, (x+3):
2x(x+3) - 5(x+3) = (x+3)(2x-5)
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