What is a a problem where the qoutient is 9 and the remainder is 5

Answer 1

For any division equation, the quotient multiplied by the divisor plus the remainder equals the dividend. Also, the dividend must be larger than the remainder.

So, you can substitute any number greater than 5 for a divisor to get the coordinating dividend.

For example,

If 8 is your divisor, 8 times 9 = 45 + 5 = 50, so 50 divided by 8 = 9R5

If 10 is your divisor, 10 times 9 = 90 + 5 =95, so 95 divided by 10 = 9R5

Answer 2

If you wanted a more GENERAL problem using unknown #s..,remember that the quotient is the answer of a division equation; one number being divided by a 2nd number. And in this case there is a remainder

Think of the top number as X and the bottom number as Y, so the quotient would be X / Y = 9 (like in your problem)

With a remainder... X = 9Y + 5

Hope this helps

Answer 3

Hi Jason,

There are many examples of such a division math exercise.

One is:

104 / 11 = 9 r 5

(11 x 9 = 99

99 + 5 = 104)