If a 0.0045 m^3 container has 1.5 moles of oxygen and is at a temperature of 303 K, what is its pressure in atm?

Answer 1

Hi Jen!

For this problem, it seems to be testing knowledge of the ideal gas law, PV = nRT. (P is pressure of the gas, V is the volume, n is the number of mols of the gas, R is the universal gas constant, and T is the temperature in Kelvin)

We can solve this equation for P, which gives us that P = (nRT)/V.

From the problem, we know that

n = 1.5

T = 303 K

V = 0.0045 m³

The universal gas constant is 8.3145 J/(mol K), which can be found on the internet or on a formula sheet.

Using this information and plugging it into our equation for the ideal gas law, we get that

P = (1.5 mol * 8.3145 J/(mol K) * 303 K ) / (0.0045 m³) = 8.40 x 10⁵ Pa

Hope this helped!