How much energy is required to turn a 0.500 kg block of ice at -15.0 degrees Celsius to steam at 125 degrees Celsius?

Answer 1

For this problem, you need to know the heat capacities of ice, water, and steam, You also need to know the heat of fusion for ice to water and the heat of vaporization form water to steam. These can be found online.

E_ice = C_ice x mass_ice x ΔT_{-15 to 0 C} where E_ice is the energy in kJ to heat ice form -15 to 0 C. C_ice is the

heat capacity of ice in the same units as mass (kJ/kg-degC)

E_fusion = H_fusion x mass_ice where H_fusion is the heat of fusion of ice. Remember that the heat of fusion

must be in the same units as the mass (kJ/kg).

E_water = C_water x mass_water x ΔT_{0 to 100 C} where C_water is the heat capacity of water ( kJ/kg-degC).

E_vap = H_vap x mass_water H_vap is the heat of vaporization of water to steam (kJ/kg)

E_steam = C_steam x mass_steam x ΔT_{100 to 125C} C_steam is the heat capacity of steam (kJ/kg-degC).

The masses are all equal to 0.5kg. You may need to convert the heat capacities and latent heats from kJ/mole to kJ/kg. Add all the E's together to get the total energy required.