Lu J.
asked 11/27/20sos confused ...Ellipse word problem .What's the planet's orbit (distance in millions of miles) about the star?
A planet moves in an elliptical orbit with a star at one of the foci. The perihelion (the smallest distance from the planet to the star) is
128.03 millions of miles and
the aphelion (the largest distance from the planet to the star) is
154.93 millions of miles.
Find an equation of the planet's orbit around the star.
[Hint: Set up a coordinate system with the star at one focus
and the major axis lying on the x-axis as in the figure. Calculate a from the equation
2a=aphelion + perihelion.
Calculate c from the equation
c=a-perihelion.
Calculate
b=a^2-c^2 Writ equation x^2/a^2 +y^2/b^2 =1
1 Expert Answer
Richard P. answered 11/27/20
PhD in Physics with 10+ years tutoring experience in STEM subjects
The problem requests that you find the equation of the ellipse in the standard form
(x/a)2 + (y/b)2 =1 and determine the values for a and b
Let the aphelion = L and the perihelion = S { Large and Small }
Standard equations for the ellipse show that S + L = 2a
The distance from the vertex to a focus is called c and c = sqrt(a2 - b2)
For this problem c = a - S which can be rearranged to get L - S = 2 sqrt( a2 - b2)
Dividing both sides by L + S = 2a ,and squaring both sides yields ( L -S)2/ (L + S)2 = 1 - b2/a2
Substituting for a with a = ( L + S) /2 generates an expression for b, which after a lot of algebra results in
(2 b)2 = L2 + S2 and from before 2a = S + L
From there it is substitution with S = 128.03 and L = 154.93 to get
a = 138.98 and b = 100.49 (million miles)
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Tom K.
You were told everything to use. In your final equation, you should have b^2, not b.11/27/20