Write an expression that defines the following as a trinomial. ​(3x – 1)(3 – x) + 4x​^2​+ 19

Answer 1

First you would want to use the foil method for the multiplying segment. Foil is first, outer, inner, last.

(3x-1)(3-x)

First: 3x * 3 = 9x

Outer: 3x * -x = -3x²

Inner: -1 * 3 = -3

Last: -1 * -x = x (two negatives multiplied =positive)

Now we combine the rest of the equation

9x - 3x² - 3 + x +4 x² + 19

We now combine like terms

9x + x = 10x

-3x² + 4x² = x²

-3 + 19 = 16

now we out them together

x² + 10x + 16 is the answer

(tip: to get the ², hold alt and type 0178)

Hope this was helpful

Answer 2

(3x-1) (3-x) = -3x^2 +10x -3

adding 4x^2. +19

we get x^2 +10x +16, a trinomial