J.R. S. answered 11/24/20
Ph.D. in Biochemistry with an emphasis in Neurochemistry/Neuropharm
Chromium atomic number 24.
Period 4, Group 6
d-block transition element
Electron configuration of a neutral Cr atom: [Ar]3d5 4s1 (see note below)
Electron configuration of Cr(III) ion: [Ar]3d3
Note: You would normally want to write [Ar]3d4 4s2 but half full and full subshells are more stable, so an electron from the 4s2 jumps to the 3d to make both the 3d and 4s subshells half-full.
Looking at neutral iron (no charge), we have atomic number 26 and it is in period 4, group 8. It is a d-block transition metal and so the electron configuration is [Ar] 3d6 4s2. Now, to become Fe3+, it has to lose 3 electrons and those will be the outermost, so it will lose the 4s2 and one electron from 3d. The resulting electron configuration for Fe(III) ion is [Ar]3d5