sin(A + B) = sinAcosB + cosAsinB
So, sin68°cos22° + cos22°sin68° = sin(68° + 22°) = sin90° = 1
Mike J.
asked 11/19/20Simplify by using the appropriate addition or subtraction formula.
sin 68° cos 22° + cos 68° sin 22°
Which answer is it
A: sin 90°
B: sin 46°
C: cos 90°
D: cos 46°
sin(A + B) = sinAcosB + cosAsinB
So, sin68°cos22° + cos22°sin68° = sin(68° + 22°) = sin90° = 1
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