
Yefim S. answered 11/17/20
Math Tutor with Experience
f(x) = 6x/(5x2 - 4x - 1) = 1/(5x + 1) + 1/(x - 1) = 1/(1 + 5x) - 1/(1- x);
1/(1 + 5x) = 1 + (-5x) + (-5x)2 + (-5x)3 + ...+ (-5x)n + ...; - 1/5 < x < 1/5;
1/(1-x) = 1 + x + x2 + ... + xn +...; -1 < x < 1,
So, f(x) = - 6x + 24x2- 126x3 + ... + [(-5)n - 1]xn +... ; -1/5 < x < 1/5