How would I write this logarithmic expression in expanded form.

Question

Log₂(5y(4x+1)⁷/³squareroot(under)2-7x

It's complicated, the square root has the 3 above it like cubic root and 2-7x under it. How will I expand it?

Answer 1

Log₂(5y(4x+1)⁷ (³√(2-7x))

= |you need only a few formulas, properties Log Log(xy)=Logx+Logy and Log x^p=p Log x.|

=Log₂5+Log₂y+7Log₂(4x+1)+(2/3)Log₂(2-7x)