What is the Standard Form of the line with x-intercept of 6 and y-intercept of 2?

Answer 1

If the y intercept is 2 our line will have an equation of the form y=Ax+2. Since we need the x intercept to be 6 we have that 0=6A+2 or A=-1/3. Thus, the equation is y=-(1/3)x+2.

Answer 2

(6,0) and (0,2) are the two points, which have a slope of 2/-6 = - 1/3

y-h = (-1/3)(x-k) plug in either point

y-2 = (-1/3)(x)

multiply by 3

3y-6 = -x

x+3y = 6

or in standard form

y=(-1/3)x + 2 where 2 is the y intercept and -1/3 is the slope

y=mx + b with m=slope, b= y intercept