A sample of gas under a pressure of 22.0 kPa has a volume of 33.0 cm3. The pressure is increased to 888 kPa, while the temperature remains constant. What v

Question

A sample of gas under a pressure of 22.0 kPa has a volume of 33.0 cm3. The pressure is increased to 888 kPa, while the temperature remains constant. What volume will the gas occupy at this pressure?

 

must show units, and must be rounded to the correct number of significant digits. Pressure for STP in atmospheric units (atm) is 1.0, STP for kilopascals (kPa) is 101.3 kPa

Answer 1

From the Boyle's law (http://en.wikipedia.org/wiki/Boyle's_law):

 

P1V1 = P2V2

 

Temperature is constant.

 

22.0kpa*33.0cm3 = 888.0kpa*V

 

So, V = 22.0kpa*33.0cm3/888.0kpa = 0.8cm3