Need help with this question

Question

A line as a slope of 4/7 and a passes through the point (-14, 3). Write an equation for the line.

Answer 1

Need help with this question

A line as a slope of 4/7 and a passes through the point (-14, 3). Write an equation for the line.

====

Use the point slope version of a line given as......y-y₁ = m (x - x_1)....where m is the slope and (x_1,y₁) is a point on the line...so we have....

y-3 = 4/7 (x - (-14)) or simplified.....y-3 = 4/7 (x+14)...check...with a sample values of (x,y)

x = 0 .......we have.....y-3 = 4/7 (0+14) =56/7 = .....y-3 = 56/7+21/7.....y= 77/7=11 (0,11) is a point on the line.

Answer 2

The formula for the equation of a line is y= mx+b, where m represents the slope and b represents the y-intercept.

The slope is equal to 4/7 and the b would be equal to the value of y when x is 0.

Firstly, calculate b by plugging in the values given for y and x.

3= 4/7*(-14)+b, 3= -8+b, b= 8+3, b= 11

Then plug the value of b into the equation y= mx+b

Therefore, the equation of a line would be equal to y= 4/7*x+11