What is the acceleration experienced by passengers on this ride in g's?

Question

The Kingda Ka roller coaster in New Jersey is the world's tallest ride of its kind. As the passenger cars are launched from rest at the start, they are accelerated uniformly to a speed of 57 m/s (128 mph) in just 3.5 s. (Assume the cars are launched in the positive horizontal direction. Indicate the direction with the sign of your answer where appropriate.)

What is the acceleration experienced by passengers on this ride in g's?

If a certain passenger has a mass of 76 kg, what is the force in newtons that acts on him during the launch phase of this ride?

Answer 1

You are given the starting speed(v_i), 0 m/s(at rest), the final speed(v_f) of 57 m/s and the time(t) of 3.5 seconds.

Use the following equation a = v_f - v_i/ t to find the roller coaster acceleration in meters per second per second. ( 16.3 m/s/s)

The want how many g's instead so since 1 g = 9.8m/s/s, divide your acceleration answer by 9.8 and that will be the number of g's( should be around 1.5 g's)

To find the force exerted on the passenger, use the Newton's second law equation, F = ma.

You found the acceleration above in m/s/s and you are given the passenger's mass of 76 kg.(1239 Newtons of force)