How far does the jet travel during the 7 s?

Question

A jet aircraft with a mass of 4,400 kg has an engine that exerts a force (thrust) equal to 60,200 N.

What is the jet's acceleration when it takes off? (Give the magnitude.)

What is the jet's speed after it accelerates for 7 s? (Assume it starts from rest.)

How far does the jet travel during the 7 s?

Answer 1

a) Draw Free Body Diagram

Ft = Thrust Force

Ft - mg = ma

a = (Ft-mg)/m = (60,200 - 4,400*9.81) / 4,400 = 3.87 m/s^2

b)

Vb = ?

Va = 0

t = 7 seconds

Vb = a*t + Va

Vb = 3.87 * 7 = 27.09 m/s

c)

Yb = (1/2) * a * t^2 = (1/2) * 3.87 * 7^2 = 94.815 m