One plane holds 50 people more than the other.together they hold 450 passangers. How many people does each hold

Answer 1

If one plane holds 50 more people than the other, then without the 50 extra people on the one plane, you can assume they will be at the same capacity. Essentially, you can find this by doing 450-50=400, then 400/2=200. Remember to not leave it at 200 for both, since one of them has 50 more passengers than the other. This means one plane will have 200 passengers and the other will have 250. You can check or prove this by adding them together to get the total that was stated in the problem: 200+250=450.

Here's the algebraic process:

x+(x+50)=450 (this is what's stated in the problem, where x is plane 1 and (x+50) is plane 2. Solve for x.)

2x+50=450 (Since there's no multiplication, just add like terms to simplify the left side.)

2x=450-50

2x=400

x=400/2

x=200 passengers for the smaller plane

200+50=250 passengers for the larger plane

Proof/Check:

200+250=450

450=450

I hope this helped!

Answer 2

Let the first plane capacity be x, and the second plane capacity be y.

Translate the first sentence to: x = 50 + y

Translate the second sentence to: x + y = 450

Substitute x into the second equation: (50+y) + y = 450

Then, solve for y:

50 + y + y = 450

Combine terms: 50 + 2y = 450

Isolate variable terms by subtracting 50 from both sides: 2y = 400

Divide by 2: y = 200

Substitute the known value of y back into the first equation: x = 50 + 200 --> x = 250

The one plane holds 250 people, and the other holds 200.

Answer 3

Let x be the first pane and y be the second plane.

y=x+50

x+x+50=450

2x=400

x=200, y=250