Denise G. answered 11/04/20
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
logb35 = logb(7x5) Expand the log
logb7 + logb5
Plugging in the values provided: 0.984 + 0.783 = 1.767
Ariel Y.
asked 11/04/20Use logb2≈0.341 , logb5≈0.783 , logb7≈0.984 to approximate the value of the given logarithm to 3 decimal places. Assume that b › 0 and b≠1
logb35≈
Thanks
Denise G. answered 11/04/20
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
logb35 = logb(7x5) Expand the log
logb7 + logb5
Plugging in the values provided: 0.984 + 0.783 = 1.767
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.