The failure tensile load for a steel wire 1.0mm in diameter is 540N. What is the failure tensile stress?

Question

Please include equations/ work to further my understanding.

Answer 1

Divide the load F by the cross sectional area A to get the stress σ.

σ = F / A

F = 540 N

A = π(d/2)² = π [(1.0 x 10^-3 m) / 2]² = ? m²

Plug in the numbers and get σ in units of N/m².